Better Solution to "Wanna Play?"
The published solution is correct, but I think there is a clearer / simpler solution possible ... you judge.
Answer: do not pay anything to play the game, you will always lose ... here is why:
At the end of the game, there will be an equal number of red and black cards in the discard pile. (always 1 red and 1 black card is added to the discard pile together - hence there is always an equal number of red and black cards in the pile)
Of the cards remaining, there will also be an equal number of red and black cards. (This is by subtraction - the initial pack of cards has an equal number of reds and blacks. From this pack we remove an equal number of reds and blacks to place on the discard pile) These remaining cards will be in our piles which must be of equal size. Therefore always a guaranteed tie.
Tuesday, January 4, 2005
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