cars on the road
Any OOB answers to this?
The solution to this one just expired a little while ago. You can use either a binomial or a Poissan modal to solve this one. Good Luck. If you want me to I will post the solution.
The probability of seeing one or more cars in any interval is one minus the probability of not seeing any. The probability of not seeing any car in 20 minutes is the product of the probabilities not seeing a car in four successive 5 minute intervals: 1 - p^4, if 'p' is the probability of non-seeing in 5 minutes. If 1 - p^4 = 609/625, then p^4 = 16 / 625, so p = 2/5. The probability of seeing one or more cars in 5 minutes is then 1 - p, or 3/5.
Hey cool, Thanks :)
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