Railroad Puzzle Yo...my answer to this puzzle was the railroad going 3 X the speed of the man... is this correct? I couldn't find the answer on the website. John Guz Sunday, August 17, 2003 Nevermind...made bad assumption the railroad travels 2 X the speed of the man John Guz Sunday, August 17, 2003 When the guy reaches the beginning of the tunnel and meets the train, he covers 1/4 of the whole tunnel length. Thus, when he'll run in another direction, he'll be in the middle of the tunnel at the moment the train enters it. Since now they need the same time to reach the end of the tunnel -- one to pass the whole tunnel, anther -- to pass the halv. Thus their speeds are related as 2:1 Dmitri Krylov Tuesday, August 19, 2003 Let: S  be the distance from the railroad to the tunnel T  be the length of the tunnel Vb be the speed of the boy Vr be the speed of the railroad Then, since Distance / Speed = Time, in the first scenario in which the boy run 1/4 of the way back: S / Vr = T / 4 / Vb or, since we're interested in the ratio of their speeds: [eq. 1] 4 * S / T = Vr / Vb In the second scenario in which the boy runs 3/4 out of the tunnel: ( S + T ) / Vr = 3 * T / 4 / Vb or, again solving for the ratio of their speeds: [eq. 2] 4 * ( S + T ) / 3 / T = Vr / Vb Set the left side of equation 1 equal to the left side of equation 2, and with a little work, you'll find: [eq. 3] 2 * S = T Then, substitute 2 * S in for T in the denominator of the left side of equation 1: 4 * S / 2 * S = Vr / Vb  or, 2 = Vr / Vb Thus, the railroad has twice the speed of the boy. anon Thursday, August 21, 2003   Fog Creek Home